I hope we all remember the square formula : \(\mathbf{(a + b)^{2} = a^{2} + b^{2}}\) + 2ab

Example: \( 56^{2} \) Step 1 : Break the number such that a=5, and b=6 Step 2 : Compute \( a^{2} \), ab and \( b^{2} \) and write as shown in the updated formula Step 3 : Notice the second row of the formula is obtained by just repeating the middle term ab of the first row. If ab and \( b^{2} \) are more than 1 digit add the carry to left part leaving 1st digit in their places.

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